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面试题 02.05. 链表求和

面试题 02.05. 链表求和

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/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) {
if(!l1)
return l2;
if(!l2)
return l1;
int c = 0;
ListNode* ret = l1;
ListNode* pre = nullptr;
while(l1 && l2)
{
l1->val += l2->val + c;
c = l1->val / 10;
l1->val %= 10;
pre = l1;
l1 = l1->next;
l2 = l2->next;
}
if(l2)
{
pre->next = l2;
l1 = l2;
}
while(c)
{
if(l1)
{
l1->val += c;
c = l1->val / 10;
l1->val %= 10;
pre = l1;
l1 = l1->next;
}else
{
pre->next = new ListNode(c);
break;
}
}
return ret;
}
};

还可以新建个链表直接递归

不想写